Question

n" term of A.P. is a If a1 +a2+a3= 102 and a 1=15, then find a10​

Answer 1

Answer:

nth term =10

Explanation:

first term=1

common different is also 1 so

the formula is an =a +(n-1)d=1+(10-1)1=1+9=১০

Answer 2

The nth term of A.P is $a_{10}$ = 216

Explanation:

n + n term = $a_{n}$ = a+(n-1)d

a→  1st term

d → common difference

$a_{1}$ = a = 15  

$a_{2}$ = a+d = 15+d  

$a_{3}$ = a+2d = 15+2d  

$a_{1}$+$a_{2}$+$a_{3}$ = 102  

15+15+d+15+2d = 102

3d = 102-45 = 67

d=67/3  

$a_{10}$ = a+(10-1)d  

= a+2d

= 15 + 2 × $\frac{67}{3}$

= 15 + 201

= 216

Hence = $a_{10}$ = 216

To learn more...

If a1,a2,a3,..........are in ap such that a1+a5+a10+a15+a20+a24=225, then a1+a2+a3+..........a23+a24 is

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A1, a2, a3,.......a24 are in A.P. and a1+a5+a10+a15+a20+a24=300. find the sum of first 24 terms of A.P.

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