Question

n term of A.P. is a . If a1 +a2+a3. = 102 and a1 =15, then find a10​

Answer 1

Step-by-step explanation:

a1+a2+a3=102

10+a+d+a+2d=102

10+10+d+10+2d=102

30+3d=102

3d=72

d=24

then

a10=a+9d

=10+9*24

10+216

236

Answer 2

Given: a1+a2+a3=102

a=15

3a+3d=102

3(15)+3d=102

3d=102-45

3d=57

d=19

a10=a+9d=> 15+9(19)=> 228