Question

n term of an arithmetic sequence is 4n+2 find sum of first 25 team of the sequence

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Answer 1

Answer:

HOPE IT HELP U

Step-by-step explanation:

n

th

term T

n

=1−4n

put, n=1, T

1

=a=1−4(1)=−3

put, n=2, T

2

=1−4(2)=−7

Common difference, d=T

2

−T

1

=−7−(−3)=−4

So, we have a=−3, d=−4, n=25, to find the sum.

Sum, S

n

=

2

n

(2a+(n−1)d)

S

25

=

2

25

(2(−3)+(25−1)(−4))

S

25

=

2

25

(−112)=25×(−51)

S

25

=−1275

This is the sum.