Question

n th term in arithmetic progressions is n+5,find the sum of first 10 terms

Answer 1

a+[n-1]d =a+[<n+5>-1]d

a+nd-d=a+nd+4d

Answer 2

Answer:

105

Step-by-step explanation:

we have general term of ap is a+(n-1)d if n=i

give dat nth term =n+5 ifn=1

T1=6 ifn=2 T2=6comparing with series a;a+d a=6 d=1so that sum of n term

n/2(2a+(n-1))d

therefore Sn=10/2(12+9)

=105