Question

(n) The area of a rectangle reduces by 20 m², if its length is increased by Im and the
breadth is reduced by 2 m. The area increases by 12 m², if the length is reduced
by 3 m and the breadth is increased by 4 m. Find the dimensions of the rectangle.
​

Answer 1

let length be x

breadth will be y

Atq

(x+1)(y-2) = xy-20

xy -2x +y -2 =xy -20

-2x +y -2=-20

..... rest of the answer is in the pic

pl mark it as BRAINLIEST

Answer 2

Answer:

x

Step-by-step explanation:

Let the length of the rectange is Lm and breadth is bm.

Now,

Area of this rectangle is L*b=Lb m square.

ATQ.

new length =L+1m

new breadth= b-2m

new area=Lb-20 m square

now

therefore area= (L+1)(b-2)=Lb-20

Lb-2L+b-2=Lb-20

Lb-2L+b-Lb=-20+2

-2l+b=-18.....(1)

Now According to second condition

new length =L-3m

new breadth=b+4 m

new area= Lb+12 m square

therefore

(L-3)(b+4)=Lb+12

Lb+4L-3b-12=Lb+12

Lb+4L-3b-Lb=12+12

4l-3b=24 .....(2)

Now,

multiplyting (1) by 2

-4l+2b=-32 ....(3)

Adding (3) and (2)

-4L+2b=-32

4L-3b=24

=> -b=-8

b=8

Putting b=8 in (1)

-2L+8=-18

-2L=-18-8

L=-26/-2

L=13

Hence length = 13m and breadth=8m