n the figure, seg AB is the chord of the circle with centre O, seg OM is
perpendicular to chord AB. If AM = 5 cm, find AB.
Answers
Answer:
OA is the radius of the circle
Perpendicular drawn from centre to a chord bisects the chord.
Therefore AM=21AB
AM=10cm
Thus, triangle OMA is right angled triangled at ∠OMA.
∠OMA=90∘.
By Pythagoras theorem,
OA2=OM2+MA2
OA=OM2+MA2
OA=(211)2+102
OA=144cm
OA=12cm
Radius of a circle is 12cm.
Option B will be the answer.
Step-by-step explanation:
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Answer:
Correct option is B)
OA is the radius of the circle
Perpendicular drawn from centre to a chord bisects the chord.
Therefore AM=
2
1
AB
AM=10cm
Thus, triangle OMA is right angled triangled at ∠OMA.
∠OMA=90
∘
.
By Pythagoras theorem,
OA
2
=OM
2
+MA
2
OA=
OM
2
+MA
2
OA=
(2
11
)
2
+10
2
OA=
144
cm
OA=12cm
Radius of a circle is 12cm.
Option B will be the answer.
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