Question

n the figure, seg AB is the chord of the circle with centre O, seg OM is

perpendicular to chord AB. If AM = 5 cm, find AB.​

Answer 1

Answer:

OA is the radius of the circle

Perpendicular drawn from centre to a chord bisects the chord.

Therefore AM=21AB

AM=10cm

Thus, triangle OMA is right angled triangled at ∠OMA. 

∠OMA=90∘.

By Pythagoras theorem,

OA2=OM2+MA2

 OA=OM2+MA2

 OA=(211)2+102

OA=144cm

OA=12cm

Radius of a circle  is 12cm.

Option  B will be the answer.

Step-by-step explanation:

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Answer 2

Answer:

Correct option is B)

OA is the radius of the circle

Perpendicular drawn from centre to a chord bisects the chord.

Therefore AM=

2

1

AB

AM=10cm

Thus, triangle OMA is right angled triangled at ∠OMA.

∠OMA=90

∘

.

By Pythagoras theorem,

OA

2

=OM

2

+MA

2

OA=

OM

2

+MA

2

OA=

(2

11

)

2

+10

2

OA=

144

cm

OA=12cm

Radius of a circle is 12cm.

Option B will be the answer.

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