Math, asked by aritra4, 1 year ago

n to the power 200 is less than 5 to the power 300.find the largest integer n that satisfies the equation.

Answers

Answered by vansh16
4
ie 25 because
5to the power 300=
5to the power 3×100 ie
125to the power 100
25 to the power 2×100 is answer

aritra4: The solution is elegant but it involves quite a bit of hit n trial process.. what if I say i raise the common power to 5 rather than 100.....n why not use logarithmic inequalitues.
Answered by Syamkumarr
5

Answer:

n = 11 will satisfy n²⁰⁰ < 5³⁰⁰

Step-by-step explanation:

Given that n²⁰⁰ < 5³⁰⁰

We know that (xᵃ)ᵇ = xᵃᵇ

Therefore, using this property, we get

(n²)¹⁰⁰ < (5³)¹⁰⁰

Raising both the sides to the power 1/100

We know that (x^{a})^{\frac{1}{a}} = x

Therefore, using this property,

=> n² < 5³

=> n² < 125

Taking square root both side, we get

=> n < \sqrt{125}

=> n < 11.18

Therefore, the largest integer n < 11.18 is 11

Therefore, n = 11 will satisfy n²⁰⁰ < 5³⁰⁰

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