Question

n triangle ABC ,if DE is parallel to BC,AD=3.2,DB=1.6,AE=x and EC=2.1,then x is *
1 point
A) 2.5
B) 3
C) 4.2
D) 2​

Answer 1

Step-by-step explanation:

ANSWER

Since DE∣∣BC

∴∠ADE=∠ABC [parallel lines cut by transversal]

& ∠AED=∠ACB

In ΔABC & ΔADE

⇒∠A=∠A [common angle]

⇒∠ADE=∠ABC

⇒AED=∠ACB

By AAA, ΔABC∼ΔADE

So

AC

AE

=

AB

AD

=

5.6

2.1

DB=AB−AD=5.6−2.1=3.5

So

DB

AD

=

3.5

2.1

=

5

3

.

Answer 2

Answer:

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