Math, asked by legendary22, 10 months ago

n triangle ABC, the measure of ∠B is 90°, BC=16, and AC=20. Triangle DEF is similar to triangle ABC, where vertices D, E, and F correspond to vertices A, B, and C, respectively, and each side of triangle DEF is 1/3
the length of the corresponding side of triangle ABC. What is the value of sinF?

Answers

Answered by almaisathwika
0

Answer:

given

angle b=90°

ac=20 and bc=16

by Pythagoras theorem

20^2=16^2+x^2

20^2-16^2=x^2

400-256=x^2

144 =x^2

√144=x

12

ab = 12

Step-by-step explanation:

1/3ab=de

1/3bc=ef

1/3ac=df

de=12*1/3=4

ef=16*1/3=5.333.……

df=20*1/3=6.66……

sinF=opp/hyp

= de/df

= 4/6.6…

Answered by forloco976
0

Answer:

Step-by-step explanation:

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