Question

N turns of a rectangular coil of length ‘l’ and breadth ‘b’ are placed in a uniform magnetic field such that
the plane of rectangular coil makes angle θ with the direction of magnetic field. Obtain the expression of
the torque applied by the magnetic field on the coil

Answer 1

Answer:

The torque on a loop in uniform magnetic field is given by

τ=

M

×

B

τ=MBsinθ [where θ is angle between normal and the plane of loop]

As the coil is inclined at an angle of 30

o

with magnetic field so area vector will be inclined at an angle of 60

o

with the field.

M=NI×πr

2

=50×2×.12×.1=1.2

B=.2T

τ=1.2×.2×sin60

∘

τ=0.2Nm