Question

n(U)=30,n(A')=15,n(B)=5,n(A intersection B)= 3, find n(A), n(A union B), n(A-B)​

Answer 1

n(A) = n(U) - n(A') = 30 - 15 = 15

n( AUB ) = n(A) + n(B) - n(A intersection B)

n( AUB ) = 15 + 5 - 3 = 17

n(A-B) = n(A) - n(A intersection B)

n(A-B) = 15 - 3 = 12

Answer 2

Answer:

n(A)=15,n(A∪B)=17.n(A-B)=12.

Step-by-step explanation:

Given:-n(U)=30,n(A')=15,n(B)=5,n(A intersection B)= 3.

To find:-n(A), n(A ∪ B), n(A-B).

Solution:-

n(A) = n(U) - n(A') = 30 - 15 = 15

n( AUB ) = n(A) + n(B) - n(A intersection B)

             = 15 + 5 - 3 = 17

n(A-B) = n(A) - n(A intersection B)

          = 15 - 3 = 12

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