Math, asked by dev200519, 9 months ago

n(u)=400,n(a)=100,n(b)=150,n(anb)=75,then n(a'nb')=?​

Answers

Answered by dnyanudhande
3

Step-by-step explanation:

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Answered by yusufkhanstar29
0

Answer:

n(a'∩b') = 175

Step-by-step explanation:

Given :- n(u) = 400 , n(a) = 100 , n(b)= 150 , n(a∩b) = 75 .

To find :- n(a'∩b') = ?

Solution :-

Step 1) formula we are going to use are

a) n(a∪b) = n(a)+n(b)- n(a∩b)

b) n(a∪b)' = n(a'∩b')

c) n(a∪b)' = n(u) - n(a∪b)

Step 2)

n(a∪b) = 100+150-75 = 175

n(a∪b)' = n(u) - n(a∪b) = 400 - 175 = 225

Therefore , n(a'∩b') = 175

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