n(u)=400,n(a)=100,n(b)=150,n(anb)=75,then n(a'nb')=?
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Answer:
n(a'∩b') = 175
Step-by-step explanation:
Given :- n(u) = 400 , n(a) = 100 , n(b)= 150 , n(a∩b) = 75 .
To find :- n(a'∩b') = ?
Solution :-
Step 1) formula we are going to use are
a) n(a∪b) = n(a)+n(b)- n(a∩b)
b) n(a∪b)' = n(a'∩b')
c) n(a∪b)' = n(u) - n(a∪b)
Step 2)
n(a∪b) = 100+150-75 = 175
n(a∪b)' = n(u) - n(a∪b) = 400 - 175 = 225
Therefore , n(a'∩b') = 175
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