N(U) = 70 n(A) = 58 n(B) = 32 n(AUB)’ = 6. Find :- a) n(A∩B) b) n(A – B) c) n(AUB) = d) n(A’∩B)
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n(U) = 70
n(AUB)’ = 6
n(AUB) = n(U) - n(AUB)’
n(AUB) = 70 - 6
n(AUB) = 64
n(A∩B)=n(A )+ n(B)− n(AUB)
n(A∩B) = 58 + 32 - 64
n(A∩B) = 26
n(A - B) = n(A) - n(A∩B)
n(A - B) =58 - 26
n(A - B) = 32
n(A’∩B) = n(B) - n(A∩B)
n(A’∩B) = 32 - 26
n(A’∩B) = 6
Answer: (a) n(A∩B) = 26 (b) n(A – B) = 32 (c) n(AUB) = 64 (d) n(A’∩B) = 6
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