Question

n(U) = 700,
n(A) = 200 ,
n(B)= 300,
n(A intersection B)= 100,
n(A' intersection B') =???​

Answer 1

n(U) = 700

n(A) = 200

Therefore, n(A') = 700 - 200 = 500

and, n(B') = 700 - 300 = 400

Therefore, n(A' intersection B') = 500 - 400 = 100

Answer 2

Answer:

At first find n(AUB)

n(AUB) = n(A) + n(B) - n(A intersection B)

so, n(AUB) = 200 + 300 - 100

so, n(AUB) = 400

we know,

n(A' intersection B') = n(AUB)'

so, n(A' intersection B') = n(U) - n(AUB)

so, n(A' intersection B') = 700 - 400

so, n(A' intersection B') = 300