Question

N+y+z=9
N squre+Y squre+Z squre=29
ny+yz+zn=?

Answer 1

Answer:

10

Explanation:

we know that, (N+Y+Z)^2=(N+Y+Z)(N^2+Y^2+Z^2+2(NY+YZ+ZN))

here (N+Y+Z)=9; (N^2+Y^2+Z^2)=29

let NY+YZ+ZN=x

then, (9)^2=(9)(29+2(x))

81=(9)(29+2x)

(81/9)=29+2x

9=29+2x

2x=29-9

2x=20

x=(20/2)

x=10

i.e. NY+YZ+ZN=10