Question

N0.8. AB and CD are respectively the smallest and longest sides of quadrilateral
ABCD. Show that angleA > angle c and angleB>angle d​

Answer 1

Answer:

It can be proved byangle sum proper.

Step-by-step explanation:

Answer 2

Answer:

AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD (see figure). Show that ∠A > ∠C and ∠B > ∠D. Given: AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD. Similarly, joining B to D, we can prove that ∠B > ∠D.

Step-by-step explanation:

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