Question

n2^-2 is paramagnetic or diamagnetic? plzz answer this...i am a bit confused​

Answer 1

Answer:

That means N2 is diamagnetic, with no unpaired electrons. In fact, its highest energy occupied molecular orbital (HOMO) is its σ2pz bonding orbital, which currently contains two electrons.

Answer 2

 $\[N_{2}^{-2}\]$   is paramagnetic.

Explanation:

• $\[N_{2}$   is a diatomic molecule with forteen electrons in it.

• When it comes to $\[N_{2}^{-2}\]$ , it has sixteen electrons in it.

• According to molecular orbital theory,the electrons are arranged as $\[\sigma 1{{s}^{2}}{{\sigma }^{*}}1{{s}^{2}}\sigma 2{{s}^{2}}{{\sigma }^{*}}2{{s}^{2}}\sigma 2{{p}^{2}}\Pi 2p_{x}^{2}\Pi 2p_{y}^{2}{{\Pi }^{*}}2p_{x}^{1}{{\Pi }^{*}}2p_{y}^{1}\]$

• For the species with forteen electrons,the electrons arranged in molecular orbitals have a different order.

• In this case,the electrons present in $}{{\Pi }^{*}}2p_{x}$  and ${{\Pi }^{*}}2p_{y}$  are unpaired.

• Since the electrons remain unpaired,the molecule is paramagnetic and is not diamagnetic.