Question

n² + 240n − 4939 = 0 solve this please ?​

Answer 1

Answer:

n = $\frac{-240 + \sqrt{37875} }{2}$ and  $\frac{-240 - \sqrt{37875} }{2}$

Step-by-step explanation:

n² + 240n − 4939 = 0

Use the quadratic formula.

n = $\frac{-b + \sqrt{b^{2} - 4ac } }{2a}$ and n = $\frac{-b - \sqrt{b^{2} - 4ac } }{2a}$

here, a = 1, b = 240 and c = -4939

n = $\frac{-240 + \sqrt{240^{2} - 4(4939) } }{2}$ and $\frac{-240 - \sqrt{240^{2} - 4(4939) } }{2}$

n = $\frac{-240 + \sqrt{57600 - 19725 } }{2}$ and $\frac{-240 - \sqrt{57600 - 19725 } }{2}$

n = $\frac{-240 + \sqrt{37875} }{2}$ and  $\frac{-240 - \sqrt{37875} }{2}$

n =  $\frac{-240 + 2 \sqrt{19339} }{2}$ and $\frac{-240 - 2 \sqrt{19339} }{2}$

n = $-120 + \sqrt{19339}$ and $-120 - \sqrt{19339}$