Question

n2-2n+8 find first 3 terms of sequence

Answer 1

Given,

Sequence $\[ = {n^2} - 2n + 8\]$

Solution,

Calculate the first three terms of sequence (n = 1, 2, 3)

$\[\begin{array}{l}n = 1\\ = {n^2} - 2n + 8\\ = {1^2} - 2 \times 1 + 8\\ = 7\\n = 2\\ = {n^2} - 2n + 8\\ = {2^2} - 2 \times 2 + 8\\ = 8\\n = 3\\ = {n^2} - 2n + 8\\ = {3^2} - 2 \times 3 + 8\\ = 11\end{array}\]$

Hence the first three terms of the sequence are $\[7,8,11\]$.