Question

N2 + 3 h2 = 2 nh3. The rate of reaction measured as ∆ nh3/∆t is 0.0002. calculate rate of reaction expressed in terms of n2 and h2.

Answer 1

Answer:

N2+3H2 →2NH3

-d/dt(H2)=0.3×10^-4M/s

Rate=1/3 -d/dt(H2) =1/2d/dt (NH3)

=>d/dt(NH3) = 2/3-d/dt(H2)

=>d/dt(NH3) = -2/3(0.3×10^-4)

=>d/dt(NH3) = -0.2× 10^-4 M/s

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