Question

N2 + 3H2 2NH3; Kc = 1.2
At the start of a reaction, there are 0.249 mol N2,
3.21 x 10-2 mol H, and 6.42 x 10-4 mol NH3 in a
3.50 L reaction vessel at 375°C. Hence reaction
will proceed in
(1) Forward direction (2) Backward direction
(3) At equilibrium (4) Stops
conlol​

Answer 1

Answer:

N2(g) + 3H2 <----> 2NH3

Kc= [NH3]2

------------- = 1.2

[N2][H2]3

We must find the Qc of the reaction in order to predict its direction.

Qc =

[NH3]2

-------------

[N2][H2]3

Substiture the given values of the reactants and the products

Qc = (6.42x10-4mol/3.5L)2

----------------------------------------------

(0.249mol/3.5L)(3.21x10-2mol/3.5L)

Suppose, the only given value is the mol, we need to divide it by the given L to find M.

Qc= 3.36x10-8

--------------------------- = 0.62

(0.07)(9.17x10-3)3

The value of Kc is 1.2 while the value of Qc is 0.62. We can say that KC>QC and at this case the reaction proceeds from left to right. The products

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Answer 2

Answer:

The value of Kc is 1.2 while the value of Qc is 0.62.We can say that Kc>Qc and in this case, the reaction proceeds from left to right i.e from reactants to products.

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