Question

N2+3H2. NH3 state which substance is oxidized or reduced also give reason​

Answer 1

Nitrogen

N₂ + 3H₂ → 2NH₃

The oxidation number of a free element, such as N₂ is 0. (The oxidation number for H₂ is also 0.)

The oxidation number for hydrogen when bonded to a nonmetal is +1, and nitrogen is a nonmetal. There are three H atoms in the ammonia molecule, so the total oxidation number for hydrogen 3(+1) = +3. The sum of the oxidation numbers in a neutral compound must equal zero, so the oxidation number for N is -3: 3(+1) + (-3) = 0.

This is a redox reaction, in which nitrogen is reduced from N₂⁰ to N⁻³, and H₂⁰ is oxidized to H⁺¹.

Notice that oxidation numbers have the + and - signs in front of the number (+1, -3), while for ions, the + or - sign goes after the number (3+, 2-). This is intentional to distinguish between the two types of notations.

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