Question

n2+3n-598 find its zeros of polynomial alpha bita

Answer 1

n2+3n-598=0

n2+26n-23n-598=0

n(n+26)-23(n+26)=0

(n+26)(n-23)=0

n+26=0;n-23=0

n=-26;n=23

The zeroes of the polynomial is -26 and 23