Question

n2-41n+400 factories

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$n^2 - 41n + 400 = (n - 16)(n - 25)$

Solution:

Given that, we have to factorize

$n^2 - 41n + 400$

$\text{Split the middle term }\\\\n^2 - 16n + 25n + 400$

$\mathrm{Break\:the\:expression\:into\:groups}\\\\\left(n^2-16n\right)+\left(-25n+400\right)\\\\\mathrm{Factor\:out\:}n\mathrm{\:from\:}n^2-16n\mathrm{:\quad }\\\\n(n - 16) +( -25n + 400)$

$\mathrm{Factor\:out\:}-25\mathrm{\:from\:}-25n+400\\\\n(n - 16) -25(n -16)$

$\mathrm{Factor\:out\:common\:term\:}n-16\\\\\left(n-16\right)\left(n-25\right)$

Thus the given expression is factored

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