Math, asked by anil7582, 10 months ago

n2-41n=400 find n with detail fraction?​

Answers

Answered by apm43
2

 \tt{ {n}^{2}  - 41n = 400} \\  \tt{n(n - 41) = 400} \\  \tt{(n - 41) =  \frac{400}{n} } \\  \tt{n =  \frac{400}{n}  + 41} \\  \tt{n =  \frac{400 + 41n}{n} }

Hope my answer will help you..

Similar questions