Question

n²-64=0 factorize following question​

Answer 1

Hi Sai It is like a rhyming word. Here is your answer:

Rewrite as given:

$n^2 -64 = 0\\n^2 -8^2= 0$

$a ^2 -b^2 =(a+b)(a-b)$

$a=x,b=8$

$(x + 8)(x-8)$

If any individual factor on the left side of the equation is equal to  0, the entire expression will be equal to  0.

$x+8 =0\\x=-8\\x-8 = 0\\x =+8$