Question

n²+6n-(a²+2a-8)=0 who ever answers this question perfectly I will mark them as the brainly​

Answer 1

Step-by-step explanation:

Given quadratic equation:n²+6n-(a²+2a-8)=0

=> n^2+6n-(a²+4a-2a-8)=0

=> n²+6n-[a(a+4)-2(a+4)]=0

=> n²+6n-(a+4)(a-2)=0

Splitting the middle term,we get

=>n²+(a+4)x-(a-2)n-(a+4)(a-2)=0

=> n[n+(a+4)]-(a-2)[n+(a+4)]=0

=> [n+(a+4)][n-(a-2)]=0

=> n+(a+4)=0 Or n-(a-2)=0

=> n = -(a+4) Or n= (a-2)

Therefore,n= -(a+4) Or n= (a-2)

hope it helps you

please mark as brainliest

Answer 2

Answer:

n=a-2, -(a+4)

Step-by-step explanation:

n^2+6n-(a^2+4a-2a-8)=0

n^2+6n-((a+4)(a-2))

n^2+(a+4)n-(a-2)n-(a+4)(a-2)=0

n(n+(a+4))-(a-2)(n+(a+4))=0

(n-(a-2))((n+(a+4))=0

n=a-2, -(a+4)