n²-7n+10 factorise the algebaric expression
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n²-7n+10
=n²-5n-2n+10
=n(n-5)-2(n-5)
=(n-2)(n-5)
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n^2-7n+10
n^2-5n-2n+10
now we will take common from the groups
n(n-5) -2(n+5)
(n-5) (n-2)
soo this is the answer
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