Question

N2 (g) + 3 H₂ (g) → 2 NH3 (9) If 28 g N₂ combines with 12 g of H₂ then maximum amount of NH3 form will be
A) 34 g
B) 17 g
C) 15g
D) 30 g​

Answer 1

Answer:

The molar mass of ammonia is 17 g/mol.

68 grams of ammonia corresponds to

17g/mol

68g

=4moles

4 moles of ammonia will be obtained from 2

4×1

=2 moles of nitrogen and 2

4×3

=6 moles of hydrogen.

The molar masses of nitrogen and hydrogen are 28 g/mol and 2 g/mol respectively.

2 moles of nitrogen corresponds to 2×28=56 grams.

6 moles of hydrogen corresponds to 6×2=12 grams.