Question

N2(g) + 3H2(g) → 2NH3(g) (a) Calculate the mass of NH3 produced if 1 kg of N2 reacts with 2kg of H2. (b) Will any of the 2 rectants remain unreacted? If yes, which one and what would be its mass left?

Answer 1

Answer:

mass of NH3 =809.52gm

H2 will be in excess.

Explanation:

N2(g) + 3H2(g) → 2NH3(g)

n(N2)=1000/28

n(H2)=2000/2=1000

limiting reagent is N2

So,

n(NH3)=2/3{n(N2)}

=2/3(2000/28)

=4000/84

mass of NH3 = (4000/84)×17

=809.52gm

H2 will be in excess.