Question

N2 + H₂
NH₃
For Preperation of 3.4 gram of ammonia.how
much mass of Nitrogen and hydrogen is required​

Answer 1

Answer:

2) if 2-conto = 3 sino.coso, where sino is not equal to como

then find the value of tano please answer it fast and no spam or i will report it

Answer 2

Answer:

Explanation:

The molar mass of ammonia is 17 g/mol.

68 grams of ammonia corresponds to  

17g/mol

68g

​

=4moles

4 moles of ammonia will be obtained from  

2

4×1

​

=2  moles of nitrogen and  

2

4×3

​

=6  moles of hydrogen.

The molar masses of nitrogen and hydrogen are 28 g/mol and 2 g/mol respectively.

2 moles of nitrogen corresponds to 2×28=56  grams.

6 moles of hydrogen corresponds to 6×2=12  grams.