N2 + H₂
NH₃
For Preperation of 3.4 gram of ammonia.how
much mass of Nitrogen and hydrogen is required
Answers
Answered by
0
Answer:
2) if 2-conto = 3 sino.coso, where sino is not equal to como
then find the value of tano please answer it fast and no spam or i will report it
Answered by
0
Answer:
Explanation:
The molar mass of ammonia is 17 g/mol.
68 grams of ammonia corresponds to
17g/mol
68g
=4moles
4 moles of ammonia will be obtained from
2
4×1
=2 moles of nitrogen and
2
4×3
=6 moles of hydrogen.
The molar masses of nitrogen and hydrogen are 28 g/mol and 2 g/mol respectively.
2 moles of nitrogen corresponds to 2×28=56 grams.
6 moles of hydrogen corresponds to 6×2=12 grams.
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