Question

n²-n-(2k+2)
zero of the
polynomial is
4 find the
value of K​

Answer 1

f(x)=n²-n-(2k+2)

f(4)=>n²-n-(2k+2)=0

=>4²-4-(2k+2)=0

=>16-4-2k-2=0

=>10-2k=0

=>10=2k

=>k=5