Question

n2+n- 42 =0
$n {}^{2} + n - 42 = 0$
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Answer 1

n² + n - 42 = 0

By using Splitting method:

n² + 7n - 6n - 42 = 0

n(n + 7) - 6(n + 7) = 0

(n - 6)(n + 7) = 0

n = 6, -7

Answer 2

Answer:

n²-6n+7n-42=0

(n²-6n)+(7n-42)=0

n(n-6)+7(n-6)=0

(n-6)(n+7)=0

n-6=0,n+7=0

n=6,n=-7