N2 reacts with H2 to form NH3. If 10L N2 reacts
with 30L H2 to form 20L NH3 under same
conditions of pressure and temperature. Show that
the data is in accordance with law of gaseous
volume. (Solve it according to Gay Lussac's of
gaseous volume OK).
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Answer:
In the reaction, N 2 +3H 2→2NH 3, the ratio by volume of N 2, H 2and NH 3 is 1:3:2. This illustrates the law of Gaseous volumes or Gay Lussac's law of combining volumes of gases.
According to this law, when gases react together to produce gaseous products, the volume of reactants and products bear a simple whole-number ratio with each other, provided volumes are measured at the same temperature and pressure.
So, the correct option is D.
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