Math, asked by mamta220reddy, 2 months ago

n28
13. There are 100 balls numbered n,, n, ny, na... 100
They are arranged in all possible ways. How many
arrangements would be there in which ball will
always be before ne ball and the two of them will
be adjacent to each other?
(a) 99!/2!
(b) 99!.2!
(c) 99!
(d) None of these
29

Answers

Answered by meenumaurya29011986
1

Answer:

They are arranged in all possible ways . How many arrangements would be there in which n28 ball will always be before n29 ball and the two of them will be adjacent to each other ? Total ways (100−2)! =98!.

So, the answer is (d) None of these

Step-by-step explanation:

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