Question

n3 + 2n2 – 5n – 6, where n is any positive integer, is always divisible by'

Answer 1

Step-by-step explanation:

n3 + 2n2 — 5n — 6 "putting n=2"

2 × 3 + 2 × 2 × 2 — 5 × 2 — 6

6 + 8 — 10 — 6

14 — (—16)

2

Answer 2

Answer:

2

Step-by-step explanation:

p(n) = n3 + 2n2 – 5n – 6 = (n – 2) (n + 1) (n + 3)

p(2q) and p(2q + 1) always have 2 as a multiple.

p(3q), p(3q + 1) and p(3q + 2) do not always have 3 as multiple

p(4q), p(4q + 1), p(4q + 2) and p(4q + 3) do not always have 4 as a multiple

p(5q), p(5q + 1), p(5q + 2), p(5q + 3) and p(5q + 4) do not have 5 as a multiple