(n3-n) is divisible by 3 explain the reason
Answers
Answered by
3
n ³ −n=n(n² −1)=n(n−1)(n+1)
Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2.
∴ n=3p or 3p+1 or 3p+2, where p is some integer.
If n=3p, then n is divisible by 3.
If n=3p+1, then n–1=3p+1–1=3p is divisible by 3.
If n=3p+2,then n+1=3p+2+1=3p+3=3(p+1)is divisible by 3.
So, we can say that one of the numbers among n,(n–1) and (n+1) is always divisible by 3.
⇒n(n–1)(n+1) is divisible by 3.
Answered by
0
Answer:
I don't now the answer iam sorry
Similar questions