Na= {an: ne N}, then N3nN4=
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Answer:
Na={an:n∈N}
The natural number set N is given by:
N={1,2,3,4,⋯}
N6={6×1,6×2,6×3,6×4,⋯}
⟹N6={6,12,18,24,30,36,42,48,⋯}
Similarly,
N8={8,16,24,32,40,48,56,64,⋯}
N6∩N8={24,48,⋯}
N6∩N8 contains the multiples of 24 = LCM(6,8).
In general,
Na∩Nb={n×LCM(a,b):n∈N}
hope this helps you
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