Question

नंबर ऑफ एटम्स प्रेजेंट इन 52 ग्राम ऑफ हीलियम इज​

Answer 1

Answer:

13×6.022×10^23 atoms

it is asked that we need to find 52 g helium have how many atom

and 4g gram mass of helium will have Na atoms

so 52/4 =13 times

13× Na atoms