Question

निम्न द्विघात समीकरण के विविक्तिकर का मान बताइये।
(x+5)^2 = 2(5x-3)​

Answer 1

Answer:

For equation of the form

ax^2 + bx + c = 0

Discriminant = b^2 - 4ac

Then,

For equation

(x+5)^2 = 2(5x - 3)

(x^2 + 25 + 10x) = 10x - 6

x^2 + 31 = 0

Discriminant = 0 - 4*1*31

= - 124

Step-by-step explanation:

Hope it will be helpful to you