Question

निम्नलिखित स्पीशीज मे रेखांकित तत्वों का ऑक्सीकरण संख्या ज्ञात कीजिये
NaH2PO4​

Answer 1

Answer:

Na +1

H +1

P +5

O -2

Explanation:

oxidation state of Na is +1

Hydrogen +1

Oxygen -2

here 2 atoms of hydrogen are present so +1×2=2

4 atoms of oxygen are present -2×4=-8

NaH2PO4 we assume that Oxidation state of P is x

+1 +2×1 +x + 4× -2=0

+3+x-8=0

-5+x=0

x=5