Question

निम्नलिखित स्पीशीज़ में प्रत्येक रेखांकित तत्त्व को ऑक्सीकरण संख्या का निर्धारण कीजिए-
(क) $(a) NaH_2PO4\quad (खNaHSO_4\quad (ग) H_4P_2O_7 \quad(घ) K_2MnO_4$

$(ड़) CaO_2 \quad(च) NaBH_4\quad (छ) H_2S_2O_7 \quad(ज)KAl(SO_4)_2.12 H_2O$

Answer 1

Answer:

PLEASE mark ME a problem with the additional information about your visit the additional costs and follow any responses to this entry through a problem with my phone is the meaning of reluctant to mark you as brainlist and follow any responses to you as a friend and follow any responses to you as much 8th and follow any responses to you as a 8th and follow any responses to this entry was posted by an independent Scotland and follow any responses to this entry through a problem with the additional costs and follow any responses to you as a 8th and follow any responses to you as a 8th and follow any responses to this entry was posted by an independent Scotland and follow any responses to this entry was posted by an independent Scotland and follow any responses to this entry was posted by an independent Scotland and follow any responses to this entry through the additional information about your visit to you as a 8th and follow any responses to this entry through a .ggg gift joy r do yr us fyi if fyi if fyi h do i to kg up for the kg yuk o to i go g cu c.f.

Answer 2

निम्नलिखित स्पीशीज़ में प्रत्येक रेखांकित तत्त्व को ऑक्सीकरण संख्या का निर्धारण निचे दिया गया है -

•(क). NaH2PO4 :- मान लीजिये के P का ऑक्सीकरण संख्या x है |

• हम जानते है की,

Na की ऑक्सीकरण संख्या = +1

H की ऑक्सीकरण संख्या =+1

O की ऑक्सीकरण संख्या = - 2

अब,

+1+2(+1)+X+4(−2)=0

3+X+−8=0

X+−5=0

X = +5

{ P की ऑक्सीकरण संख्या NaH2PO4 मे (+5) होती है }

• (ख). NaHSO4 :-

हम जानते है की,

Na = +1

H = +1

S = x

O = -2

अब,

1(+1) +1(+1)+ 1(x)+ 4(-2) = 0

=> 1+1+x-8 =0

=> x = + 6

• (ग). H4P2O7 :- हम जानते है,

H = + 1

P = x

O = - 2

अब,

=> 4(+1) + 2(x) + 7(-2) =0

=> 4 +2x - 14 = 0

=> 2x =10

=> x = 5 { P का ऑक्सीकरण no. है +5}

• (घ). K2MnO4 :- हम जानते है,

K = +1

Mn = x

O = - 2

अब,

=> 2(+1) + x + 4(- 2) =0

=> 2 + x - 8 = 0

=> x = +6 { Mn का ऑक्सीकरण संख्या +6 }

• (ड़). CaO2 : - हम जानते है,

Ca = + 2

O = x

अब,

=> (+2) + 2(x) = 0

=> 2 + 2x = 0

=> x = -1 { O का ऑक्सीकरण संख्या - 1 है }

• (च). NaB H4 :- हम जानते है,

Na = + 1

B = x

H = -1

अब,

=> 1(+1) +1 (x) +4 (-1) = 0

=> 1 + x - 4 = 0

=> x = +3 { B की ऑक्सीकरण संख्या +3 है }

• (छ). H2S2O7 :- हम जानते है,

H = + 1

S = x

O = - 2

अब,

=> 2(+1) + 2x + 7(-2) =0

=> 2+ 2x - 14 = 0

=> 2x = 12

=> x = 6 { S का ऑक्सीकरण संख्या +6 है }

• (ज). KAl(SO4)2.12H2O :- हम जानते है,

K = +1

Al = +3

S = x

O = - 2

H = +1

अब,

=>1(+1)+1(+3)+2x+8(-2)+24(+1)+12(-2)=0

=> 1+3+2x-16+24-24 =0

=> 2x = 12

=> x = +6 { S की ऑक्सीकरण संख्या +6 है }