Question

निम्नलिखित समीकरणों में से प्रत्येक समीकरण के चार हल लिखिए:
(i) 2x+y=7
(ii) Piex+y=9
(ii) x=4y

koi ans batadijiye na if u know I will mark as brainleast​

Answer 1

Step-by-step explanation:

I. 2x + y = 7

a. x= -1

-2 + y = 7

=> y = 7 + 2 = 9

(-1, 9)

b. x = 0

0+ y = 7

=> y = 7

(0,7)

c. x = 1

2 + y = 7

=> y = 7 -2 = 5

d. x=2

4 + y = 7

=> y = 7 -4 = 3

2.

$\frac{22}{7} x + y = 9$

$a. \: x = - 1 \\ = > \frac{22}{7} \times - 1 + y = 9 \\ = > - \frac{22}{7} + y = 9 \\ = > y = 9 + \frac{22}{7} \\ = > y = \frac{63 + 22}{7} = \frac{85}{7} = 12.14$

(-1, 12.14)

$b. \: x = 0 \\ = > \frac{22}{7} \times 0 + y = 9 \\ = > 0 + y = 9 \\ = > y = 9$

(0, 9)

$c. \: x = 1 \\ = > \frac{22}{7} \times 1 + y = 9 \\ = > \frac{22}{7} + y = 9 \\ = > y = 9 - \frac{22}{7} = \frac{63 - 22}{7} = \frac{41}{7} = 5.85$

(1, 5.85)

$d. \: x = 2 \\ = > \frac{22}{7} \times 2 + y = 9 \\ = > \frac{44}{7} + y = 9 \\ y = 9 - \frac{44}{7} = \frac{63 - 44}{7} = \frac{19}{7} = 2.71$

(2, 2.71)

3. x =4y

a. y = 4 x -1

=> x = -4

(-4,-1)

b. y = 0

=> x = 4 x 0 =0

(0,0)

c. y = 1

=> x= 4 x 1 = 4

(4,1)

d. y=2

=> x = 4 x 2 = 8

(8,2)

Answer 2

Answer:

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