Hindi, asked by pvarshney6182, 1 year ago

निम्नलिखित विभाजन कीजिए : (i)  28x^4 \div 56x (ii)  -36y^3 \div 9y^2 (iii)  66pq^2r^3 \div 11qr^2 (iv)  34x^3y^3z^3 \div 51xy^2z^3 (v) 12a^8b^8 \div (- 6a^6b^4)

Answers

Answered by nikitasingh79
1

Answer Explanation:

1)

28x⁴ ÷ 56x

= (2×2×7×x×x³)/( 2×2×2×7×x)

= x³/2

 

2) –36y³ ÷ 9y²

= (-2×2×3×3×y×y²) /( 3×3×y²)

= - 4y

 

3) 66pq²r³ ÷ 11qr²

= (11×6× p× q×q×r×r²)/(11× q×r²)

= 6pqr

 

4) 34x³y³z³ ÷ 51xy²z³

(2×17× x×x²×y×y²×z³)/(3×17× x× y²× z³)

= (2/3) x²y

 

5) 12a^8b^8 ÷ (– 6a^6b⁴)

= (2×6×a²×a^6×b⁴×b⁴)/(-2×3×a^6×b⁴)

= - 2a²b⁴

​​​​​​​​​​​​​​​आशा है कि यह उत्तर आपकी अवश्य मदद करेगा।।।।  

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Answered by ItzCuteChori
1

\huge{\boxed{\red{\boxed{\mathfrak{\pink{Solution}}}}}}

1) 28x⁴ ÷ 56x

= (2×2×7×x×x³)/( 2×2×2×7×x)

= x³/2

x³/2

2) –36y³ ÷ 9y²

= (-2×2×3×3×y×y²) /( 3×3×y²)

= - 4y

3) 66pq²r³ ÷ 11qr²

= (11×6× p× q×q×r×r²)/(11× q×r²)

= 6pqr

4) 34x³y³z³ ÷ 51xy²z³

= (2×17× x×x²×y×y²×z³)/(3×17× x× y²× z³)

= (2/3) x²y

5) 12a^8b^8 ÷ (– 6a^6b⁴)

= (2×6×a²×a^6×b⁴×b⁴)/(-2×3×a^6×b⁴)

= - 2a²b⁴

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