Question

निम्नलिखित वर्ग समीकरण का हल सूत्र विधि से ज्ञात कीजिए 6x2+x-2=0​

Answer 1

Step-by-step explanation:

6x²+ x - 2 = 0

6x² - 3x + 4x - 2 = 0

3x(2x - 1)+ 2(2x-1) =0

(3x +2) (2x - 1) = 0

Answer 2

Answer:

4x2 – 3x + 7

⇒ 4x2 – 3x + 7x°

∵ All the exponents of x are whole numbers.

∴ 4x2 – 3x + 7 is a polynomial in one variable.

(ii)

∵ All the exponents of y are whole numbers.

∴ is a polynomial in one variable.

(v) x10 + y3 + t50

∵; Exponent of every variable is a whole number,

∴ x10 + y3 + t50 is a polynomial in x, y and t, i.e. in three variables.