Na of molecules in 100 g of ammonia
is more than the 100 g of n2
Answers
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MOLAR mass of Ammonia = NH3 =14 + 1×3=17g/mol
Moles of Ammonia = Mass/molar mass
Moles of ammonia =100/17
Moles of ammonia = 5.8mol
Moles of ammonia = number if molecules of NH3/Avagadro number
Number of molecules of ammonia = Moles of NH3 × avagadro number
Number of molecules of NH3b= 5.8 ×6.023×10^23
Number of molecules of ammonia = 34.9 ×10^23
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Mass/molar mass=number of molecules /avagadro number
Number of molecules = mass/molar mass×avagadro number
Number of molecules of N2 = 100/28×6.023×10^23
Number of molecules of N2=3.57×6.023×10^23
Number of molecules of N2 = 21.5×10^23
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So.........
Molecules of ammonia in 100g are more than molecules of N2 in 100g
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