na2 s2 o3 oxidation number
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What is the oxidation state of sulfur in Na2S2O3? There is a set of rules you can use, or just look to the positions of the atoms in the periodic table. the Na will always be +1 in a compound (its in column 1) and the O, with a very few exceptions will always be -2 in a compound (Its in column 6)
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Given :
Compound Sodium thiosulfate
Chemically :
Na₂S₂O₃
Find oxidation state or number of S in given compound .
We know :
O.N. of Na = + 1 [ All alkali metals have O.N. + 1 ]
O.N. of O = - 2 [ 99% we - 2 and rest - 1 in peroxide or super oxide ]
Let say O.N. of S is x in given compound :
2 + 2 x - 6 = 0
2 x - 4 = 0
2 x = 4
x = + 2 .
Thus the O.N. of S in Sodium thiosulfate or Na₂S₂O₃ is + 2 .
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