Math, asked by tejkushwaha629, 2 months ago

na2co3 is dissolve in water when contains 10 molecules of water ña2co3•10h2O​

Answers

Answered by pooja7780
1

Answer:

Let, ‘x’ g of Na2CO3.nH2ONa2CO3.nH2O is taken and heated to remove the water completely. After that the weight becomes ‘y’ gram. Here ‘y’ g is weight of remaining Na2CO3Na2CO3 only. Lose of water is (x - y) g

‘y’ g Na2CO3Na2CO3 ≡ (x - y) g H2OH2O

106 g Na2CO3Na2CO3 ≡ (x−y)×106y(x−y)×106y g H2OH2O

mole no, n = (x−y)×106y×18(x−y)×106y×18

The value of n will be ≈ 10

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