Na2CO3.xH2O has 46%H2O by mass find x
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Mass of the compound(Na2CO3) will be-
23×2 + 12 + 16×3 = 46+12+48=106
Total mass including water of crystallisation will be- 106 + 18x
Given 46% of the total mass is H20
Therefore, 46/100 × (106 + 18x) = 18x
or, 4876 + 828x = 1800x
or, 4876 = 972x
or, x = 5.016 ~ 5
Therefore water of crystallisation for Na2CO3 will be 5. Therefore x=5.
23×2 + 12 + 16×3 = 46+12+48=106
Total mass including water of crystallisation will be- 106 + 18x
Given 46% of the total mass is H20
Therefore, 46/100 × (106 + 18x) = 18x
or, 4876 + 828x = 1800x
or, 4876 = 972x
or, x = 5.016 ~ 5
Therefore water of crystallisation for Na2CO3 will be 5. Therefore x=5.
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