Na2co3.xh2o loses 14.5% h2o on heating.. Value of x is
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Answered by
2
x 100Dear Student,
Given: NagCO3.XH20 loses 14.5 H2O or 14.5%
mass on heating
Molar mass of salt (Na2CO3.xH20 )-106+18x
% H30massof water
molar mass of salt18
106+1814.5
on solving we get x-1
Regards!x 100
Answered by
4
Na2CO3= (2×23)+12+48 =106
Accordingly, by law of percentage of mass
18x/(106+18x) = 14.5/100
Now on solving you will get the value of x.
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